what equals 180 in multipucation
x2 - 2x + 55 = 90x2 - 2x - 35 = 0(x+5)(x-7) = 0x = -5, 7
Here's the factor tree: 180 =90x2 =45x2x2 =15x3x2x2 =5x3x3x2x2 or 2 x 2 x 3 x 3 x 5 (In index form this is 22 x 32 x 5)
There are nine numbers which contain only one digit. There are 90 numbers which contain two digits. There are 900 numbers which contain three digits. There is one number which contains four digits.Therefore, the number of digits is equal to (9x1)+(90x2)+(900x3)+4 = 2893 digits. If this includes spaces, there would be 999 spaces, therefore there would be 3892 keystrokes.
Use any letter for the number, for example, x. The equation is:x + x2 = 90This should be converted to standard form before proceeding:x2 + x = 90x2 + x - 90 = 0This can easily be factored. You need two numbers (one positive, one negative), whose sum is +1, and whose product is -90.(x + 10)(x - 9) = 0This gives you two solutions for x:x + 10 = 0x = -10or:x - 9 = 0x = 9Note: it is quite common for a quadratic equation to have two solutions.Use any letter for the number, for example, x. The equation is:x + x2 = 90This should be converted to standard form before proceeding:x2 + x = 90x2 + x - 90 = 0This can easily be factored. You need two numbers (one positive, one negative), whose sum is +1, and whose product is -90.(x + 10)(x - 9) = 0This gives you two solutions for x:x + 10 = 0x = -10or:x - 9 = 0x = 9Note: it is quite common for a quadratic equation to have two solutions.Use any letter for the number, for example, x. The equation is:x + x2 = 90This should be converted to standard form before proceeding:x2 + x = 90x2 + x - 90 = 0This can easily be factored. You need two numbers (one positive, one negative), whose sum is +1, and whose product is -90.(x + 10)(x - 9) = 0This gives you two solutions for x:x + 10 = 0x = -10or:x - 9 = 0x = 9Note: it is quite common for a quadratic equation to have two solutions.Use any letter for the number, for example, x. The equation is:x + x2 = 90This should be converted to standard form before proceeding:x2 + x = 90x2 + x - 90 = 0This can easily be factored. You need two numbers (one positive, one negative), whose sum is +1, and whose product is -90.(x + 10)(x - 9) = 0This gives you two solutions for x:x + 10 = 0x = -10or:x - 9 = 0x = 9Note: it is quite common for a quadratic equation to have two solutions.
no because a triangle can only have sides that equal up to 180 degrees. Right angles=90 degrees 90x2=180 and a triangle has 3 sides so thus meaning it is impossible to have two right angles
area of a triangle = 0.5 * base * height. Hence, the base of the triangle = 2 * area / height = 2 * 90 [in2] / 12 [m] we know 1 [m] = 39.37 [in] or equivalently, 1 = 39.37 [in/m] Therefore, base = 2 * 90 [in2] / (12 [m] * 1) = 2 * 90 [in2] / (12 [m] * 39.37 [in/m] ) = 2 * 90 [in] / (12 * 39.37 ) = 0.381 [in] =============== area=basexheight/2 bring two over to ninety side 90x2=180 180=12xbase 180/12=15 base=15 =============== The second author above has forgotten about the units -- the area given is in square inches and the height is in meters.
1 Let the height and width be 4x and 3x respectively2 So: 0.5*4x*3x*15 = 585.225 => 90x2 = 585.2253 Divide both sides by 90 and then square root each side4 Therefore: x = 2.55 so height = 4*2.55 = 10.2 cm, width = 3*2.55 = 7.65 cm5 Hypotenuse: 5*2.55 = 12.75 cm because it's part of a Pythagorean triple6 Area: 2*(0.5*10.2*7.65)+(15*12.75)+(15*10.2)+(15*7.65) = 537.03 cm27 Check: 0.5*10.2*7.65*15 = 585.225 cubic cm
For any number, there is only one prime factorisation. That is a very important theorem of arithmetic and asking "what arethe prime factorisation for a number" makes no sense.The prime factorisation (factorazation, even) of 160 is 2*2*2*2*2*5
The least common multiple of 12, 18, and 30 is 180.First break the number down into their prime factors:12 = 22 x 318 = 2 x 3230 = 2 x 3 x 5To find the LCM (lowest common multiple) multiply all the prime factors in the lists together. However, primes occurring in moire than one list only have to be counted once.So 2 x 2 x 3 x 3 x 5 = 180
The time it takes to raise a GPA (grade-point average) from 2.0 to 3.0 depends on how many course hours are contributing to that 2.0 average thus far, how much time is left in school, and what subsequent grades one is able to earn. GPA (cumulative) is the sum of the grades for every course hour divided by the number of course hours taken (or planned). 1st example: If a student has completed only one semester so far, of 15 hours, with grades of C (2.0) in every class, his GPA is 2.0. He can raise his cumulative GPA to 3.0 after just one more semester by taking 15 more hours and earning grades of A in every class. (15 hours at 2.0 and 15 hours of 4.0 averages to a GPA of 3.0.) 2nd example: If another student has completed 2 full years at a 4-year college and holds a 2.0 average at that point, she must, in the next 2 years, take as many classes as in years 1-2 and earn all A's to average a 3.0 upon graduation. 3rd example: If a third student is holding a 2.0 average after 3 years (6 semesters) at a 4-year college, it is no longer possible to raise his average to a 3.0 by graduation. Earning all A's for the final year (assuming an equivalent course load) produces, in this example, only 30 hours at 4.0 to balance against 90 hours at 2.0. The cumulative grade-point average will be only 2.5. The calculation: GPA = ((90x2)+(30x4))/120 = (180+120)/120 = 300/120 = 2.5. For this student, with 3 years of C's, raising his average to 3.0 in one more year isn't possible. He would have to take and earn all A's in a triple load of 90 hours of courses his senior year! Alternatively, he could drag out his degree to 6 years (by avoiding some required courses until the last semester), and earning all A's for years 3-6.