13010 years ago
Remembering there was no year zero, it was 4699 years.
1500 bc came before 753 bc. Year numbers go down in "bc", where the next year has a lower number than the previous year all the way to 1 bc. The year after 1 bc is 1 ad. To give an example, a tree that sprouted in 1500 bc would be about 753 years older by 753 bc and about 1500 years older by year 1 bc. On 1 ad, it would be 1501 years old.
approx. 4699 yearsjust add the current year to the BC year(2013 + 2686 =4699)
The year 1 BC was immediately followed by the year 1 AD. So from the end of 25 BC to the end of 1 BC was 24 years and from the beginning of 1 AD to the beginning of 16 AD was 15 years. So the number of years between the 25 BC and 16 BC = 24 + 15 = 39 years.
I am pretty sure that it was 10,000 years ago, and if you want to be more specific, 10,010 years ago.
10000 BC
1236 a.D* * * * *More like 7988 BC.(Answer dated April 2013).-7988
We're now in the year 2015.2015 - 10,000 = -7,985If you were born in the year 7986 BCE, you would turn 10,000on your birthday this year.
One hundred years before 50 BC, it was the year 150 BC!
13010 years ago
In terms of "BC" years, 750 BC is 50 years after 800 BC because BC years count down from the year before, instead of up like we currendly do in AD. For example, if this year were 2009 BC, next year would be 2008 BC.
Take the BC year and add it to the AD year with present year and bc & ad
32,990 bc
The Great Sphinx carved c2575 BC - c2465 BC. Stonehenge, unlike the sphinx, is not one entity as it consists of various works. These are estimated from c2500 BC to c3100 BC. Therefore the answer is - no.
Yes. The last dinosaur (unless your count birds) died 65,000,000 years ago.
1500 bc came before 753 bc. Year numbers go down in "bc", where the next year has a lower number than the previous year all the way to 1 bc. The year after 1 bc is 1 ad. To give an example, a tree that sprouted in 1500 bc would be about 753 years older by 753 bc and about 1500 years older by year 1 bc. On 1 ad, it would be 1501 years old.