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It's 3 molecules of water. A water molecule has 3 atoms. So there are 9 atoms in 3H2O

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Q: How many atoms are in 3H2O?
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Related questions

How many number of elemnets in 3h2o?

3H2O has 6 hydrogen atoms and 3 oxygen atoms.


How many hydrogen atoms are in 3H2O?

9


How many compounds are in 3H2O?

3 Hydrogen atoms, 2 Oxygen atoms.


How many atoms are in (SO)3?

It's 3 molecules of water. A water molecule has 3 atoms. So there are 9 atoms in 3H2O


How many molecules are in the formula 3H2O?

There are 6 molecules in the formula 3H2O: 3 molecules of water (H2O) each composed of 3 atoms (2 hydrogen and 1 oxygen).


What does 3H2O represent?

3H2O represents three molecules of water. Each water molecule (H2O) consists of two hydrogen atoms and one oxygen atom.


What the symbol of 2NaAlO 2 plus 3H2o?

2NaAlO 2+3h2O


How many molecules are present in 3 h20?

There are 3 molecules of water present in 3H2O. Each H2O molecule consists of 2 hydrogen atoms and 1 oxygen atom.


What is the number and type of atom in 3 H2O?

In 3 molecules of H2O, which is 3H2O, there are 6 hydrogen atoms and 3 oxygen atoms. You multiply the coefficient of 3 times the subscript of each element. When there is no subscript, it is assumed to be 1.


What is 3H2o SO4?

3H2O + SO4 is not a defined chemical formula. 3H2O represents 3 water molecules and SO4 represents sulfate. The reaction or compound formed would depend on the specific conditions under which these substances are combined.


What is the mass of BeC2O4 if 3.21g of BeC2O4-3H2O is heated to 220 degrees Celsius?

BeC2O4 = 97.0 g/1 mol BeC2O4-3H2O = 151.0 g/1 mol 3.21 g BeC2O4-3H2O * 1 mol/151.0 g = 0.021258 mol BeC2O4-3H2O 0.021258 mol BeC2O4-3H2O * 97.0 g/1 mol = 2.06 g BeC2O4


How would you demonstrate that the following chemical equation illustrates the conversation of mass in chemical reactions 3naoh h3po4--na3po4 3h2o?

To demonstrate the conservation of mass in the chemical reaction 3NaOH + H3PO4 -> Na3PO4 + 3H2O, you would need to show that the total mass of the reactants (3NaOH + H3PO4) is equal to the total mass of the products (Na3PO4 + 3H2O). This can be done by calculating the total mass of each side of the equation using the molar masses of the compounds and ensuring they are equal. This illustrates that mass is conserved in the reaction.